model 2 gain lost percentage Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC CHSL 2011]

The cost price of 20 oranges is same with selling price of 16 oranges. The profit percentage is

a) 30%

b) 20%

c) 16%

d) 25%

Answer: (d)

Gain per cent = ${20 - 16}/16 × 100 = 25%$

Using Rule 8,

Here, x = 20, y = 16

Gain % = $({x - y}/y) × 100$

= ${20 - 16}/16 × 100 = 4/16 × 100 = 25%$

Question : 22 [SSC CGL Prelim 2003]

If the cost price of 50 oranges is equal to the selling price of 40 oranges, then the profit per cent is

a) 5%

b) 10%

c) 25%

d) 20%

Answer: (c)

Let the C.P. of one orange = 1

C.P. of 40 oranges = Rs.40

and S.P. of 40 oranges = Rs.50

Profit = (50 - 40) = Rs.10

Profit % = $10/40 × 100$ = 25%

Using Rule 8,

Here, x = 50, y = 40

Profit % = $({x - y}/y) × 100$

= $({50 - 40}/40) × 100$ = 25%

Question : 23 [SSC CPO S.I.2010]

If the selling price of 4 articles is equal to the cost price of 5 articles, the profit percent is

a) 20%

b) 22$1/2$%

c) 30%

d) 25%

Answer: (d)

If the CP of each article be Rs.1 then

CP of 4 articles = Rs.4

SP of 4 articles = Rs.5

Profit percent = ${5 - 4}/4 × 100 = 25%$

Using Rule 8,

Here, x = 5, y = 4

Profit % = $({x - y}/y) × 100$

= $({5 - 4}/4) × 100 = 100/4$ = 25%

Question : 24 [SSC CGL Prelim 2002]

The cost price of 18 articles is equal to the selling price of 15 articles. The gain per cent is :

a) 15%

b) 20%

c) 18%

d) 25%

Answer: (b)

Gain % = ${18 - 15}/15 × 100$

= $3/15 × 100 = 20%$

Using Rule 8,

Here, x = 18, y = 15

Gain% = $({x - y}/y) × 100$

= $({18 - 15}/15) × 100$

= $3/15 × 100$ = 20%

Question : 25 [SSC CHSL 2011]

A man sells 320 mangoes at the cost price of 400 mangoes. His gain percent is :

a) 15%

b) 20%

c) 10%

d) 25%

Answer: (d)

Using Rule 8,

Loss per cent = ${400 - 320}/400 × 100$

= $80/400 × 100 = 20%$

IMPORTANT quantitative aptitude EXERCISES

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